A Brief Lesson On Torque And How It Affects Performance
There can be no horsepower without torque. I’m not just saying that because I like an engine with a nice, thick, low-end power band. When it comes to internal combustion engines, horsepower is mathematically connected to torque. You can’t have one without the other.
Now I’ll be the first to admit I’m not an engineer. That’s why I contacted a friend of mine from my Ford days who is an engineer to help me explain this. Not only that, he’s driven an E46 M3 through numerous Michigan winters just for the fun of it, so he’s certainly not against high-revving superstar performers. But he’s forgotten more about engines and horsepower and performance applications than most of us will ever know, so I tend to listen when he talks cars. We’ll call him Bob, because Bob’s line of work requires a certain level of anonymity.
With that in mind, Bob says:
Why 5252? Because that’s the RPM where horsepower and torque cross on a normally scaled dyno plot. Seriously, Google “engine dyno plot” and look at the images. Now, there are some fairly technical reasons why 5252 is the magic number, and if you really want to get that deep into it, there are plenty of technical colleges that offer great engineering programs. Or Google can give you the two-page overview. For our purposes, just know that this is how engines do what they do.
It’s also how dynos do what they do. When you pull onto a rolling road to see how much horsepower you gained (or lost) from your spanking-new cold air induction kit, the dyno isn’t actually measuring horsepower. It measures torque, engine speed, then uses the above equation to calculate horsepower as measured at the wheels.
That’s all well and good, but what does that mean for real-world applications? There are many different engine combinations that make power in different ways, but for our purposes we’ll break it down to just a couple of arrangements.
One: A large displacement engine that operates at a slower speed. The size allows for larger volumes of air to enter at one time, creating a bigger boom with each firing of the spark plug. This generally results in more rotational force at a slower speed, and that means more horsepower is also available at a slower speed. Typically in these applications, the trade-off is weak performance higher in the rev range, where horsepower likes to live.
Two: A small displacement engine that operates at a higher speed. It might be half the size of large engines, but it makes up for this deficit by spinning faster, thus pushing the same amount of air. The trade-off is a lack of rotational force at lower speed for more horsepower up high, and depending on who you talk to, shorter engine life spans because of extra wear and tear. Working twice as hard does come with consequences.
Per Bob, engines are basically air pumps. The more air you take in, the more fuel you can mix with it to make power. But you also have to “pump” that air out fast enough to make room for more air. Forced induction can certainly help shove more air through the engine, but if the engine can’t get the air back out, it won’t make power.
This is what happened to cars in the 1970s - emission regulations required engines to operate with restrictive exhaust systems, and the U.S. market was especially brutal. Big V8s still made gobs of torque, but airflow restrictions didn’t let them rev. They still had plenty of twist down low, but ran out of steam just when the real fun was about to begin.
The million-dollar question then is which is better: High revving, small displacement engines or large-displacement engines with lower rev limits? That is really a matter of opinion, because there are so many other factors to consider. Forced induction and gearing certainly make a difference in performance, as does mass, size, and intended use. And it’s not like manufacturers aren’t making big engines that rev like crazy or small engines with lots of twist. But we can at least draw some general conclusions.
In racing applications, having a wide RPM-range to work with provides more flexibility on the track. Low-end power isn’t nearly as critical because the engine is always operating in the upper ranges. F1 is the perfect example of this with the current 1.6-litre engines making roughly 600bhp and spinning to 15,000 RPM.
In street applications, it’s not that simple. It would take a massive clutch drop for that F1 engine to move a Dodge Ram pickup truck despite having 600 horsepower, and I shudder to think of how long such a mill would last toting three tonnes of ‘Murica. That’s the difference torque makes - it gets things moving so horsepower can keep things moving. And if you’re spending a majority of your time on the street running in the lower RPM range, having something with strong low-end power is at the very least going to be livelier to drive, and easier to enjoy for every day use, because it gets you moving quicker.
But now we’re talking opinion, and that’s for another time. Hopefully you’ve learned a bit more about torque and how it applies to the cars we love.
Comments
Awesome. Can we get more please? :D
“engines are basically air pumps”… I have an engine powered air pump. Does that mean I have two air pumps in one? If I put a turbo on it, will that make it three air pumps in one and I just remembered it is oil cooled so it’s actually basically an oil pump and an air pump with air pump attachments and WHY DO I HAVE A HEADACHE?
:)
A Veyron is 5 air pumps? Damn that is overpriced.
“WHY DO I HAVE A HEADACHE?” LOLOLOLOLOLOLOLOLOLOLOL
Comclusion: Air in + gasoline in + air out = POWAAAAAAAAAAAAAAAAAAAAAA + Your Honda can’t do this
So you are saying Hondas don’t move?
This basically sums it all up:
Always enjoy reading your articles. Great job
very informative blog….I always wondered how torque and horsepower are related..this blog sums it up…great work!!!!
Soooooo…… how do I save this post?
Click the ‘’remind me’’ button at the end in the right side of the post, actually at the bottom
Bookmark it?
You can right-click and “Save webpage as…” and it’ll download the entire thing- on Chrome at least.
ok thanks everyone
Does the formula only work if you put in torque in lb-ft unit or should it work for nm as well?
For kW and Nm its [RPM x Nm / 9550 = kW]
Finally this is explained. Thank you.
That calculation (torque x rpm /5252) is i believe for lb-ft and hp unit, i use newtonmeter and hp which i believe is not crossed in 5252 rpm, i dont know about kilowatt, but do i should convert those units to get it right or is there any diffrent calculation for different unit?
for kilowatt, you need to divide it by 60 or 60000 if I’m not wrong.